---
title: "Advent of Code 2022: Day 4"
url: https://perrotta.dev/2022/12/advent-of-code-2022-day-4/
last_updated: 2026-01-03
---


Refer to the [previous post]({{< ref "2022-01-28-advent-of-code" >}}) about AoC,
and to the [git repository](https://github.com/thiagowfx/adventofcode) with my
solutions in Python 3.

Link to [Day #4](https://adventofcode.com/2022/day/4) puzzle.

Find overlapping cleaning assignment pairs.

```python
#!/usr/bin/env python3
import sys


def eitherContains(e1, e2):
    if e1[0] >= e2[0] and e1[1] <= e2[1]:
        return 1
    elif e2[0] >= e1[0] and e2[1] <= e1[1]:
        return 1
    else:
        return 0


def anyOverlap(e1, e2):
    return int((e1[1] >= e2[0]) and (e1[0] <= e2[1]))


def main():
    with open(sys.argv[1]) as input:
        lines = input.read().splitlines()

    totalEitherContains = 0
    totalAnyOverlap = 0

    for line in lines:
        # [['2', '4'], ['6', '8']]
        [e1, e2] = [el.split('-') for el in line.split(',')]
        # [2, 4], [6, 8]
        e1, e2 = list(map(int, e1)), list(map(int, e2))

        totalEitherContains += eitherContains(e1, e2)
        totalAnyOverlap += anyOverlap(e1, e2)

    # Part 1
    print(totalEitherContains)

    # Part 2
    print(totalAnyOverlap)


if __name__ == '__main__':
    main()
```