LeetCode #100: Same Tree
β’ 147 words β’ 1 min β’ updated
python
# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, val=0, left=None, right=None):
# self.val = val
# self.left = left
# self.right = right
class Solution:
def isSameTree(self, p: Optional[TreeNode], q: Optional[TreeNode]) -> bool:
if not p and not q: # is None
return True
if (not p and q) or (p and not q):
return False
return p.val == q.val and self.isSameTree(p.left, q.left) and self.isSameTree(p.right, q.right)Alternatively:
python
# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, val=0, left=None, right=None):
# self.val = val
# self.left = left
# self.right = right
class Solution:
def isSameTree(self, p: Optional[TreeNode], q: Optional[TreeNode]) -> bool:
if not p and not q: # is None
return True
if not p or not q:
return False
if p.val != q.val:
return False
return self.isSameTree(p.left, q.left) and self.isSameTree(p.right, q.right)