LeetCode #3662: Filter Characters by Frequency
β’ 38 words β’ 1 min
LeetCode #3662: Filter Characters by Frequency:
python
from collections import Counter
class Solution:
def filterCharacters(self, s: str, k: int) -> str:
ans = []
counter = Counter(s)
for c in s:
if counter[c] < k:
ans.append(c)
return ''.join(ans)